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Question

If 3+x2yi and x2+y+4i are conjugate of each other, then find |x|+|y|.

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Solution

since, 3+x2yi & x2+y+4i are conjugate of each other
Therefore, 3+x2yi=x2+y4i
on comparing real parts & imaginary parts, we get
3=x2+y ...(1)
x2y=4 ...(2)
from (1) & (2), we get
x=1 & y=4
Therefore, |x|+|y|=5

Ans: 5

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