If −3+x2yi and x2+y+4i are conjugate of each other, then find |x|+|y|.
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Solution
since, −3+x2yi & x2+y+4i are conjugate of each other Therefore, −3+x2yi=x2+y−4i on comparing real parts & imaginary parts, we get −3=x2+y...(1) x2y=−4...(2) from (1) & (2), we get x=1 & y=−4 Therefore, |x|+|y|=5 Ans: 5