If $3^{x} = 6561,$ then $3^{x - 3}$ is ?

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Solution

$3^{x} = 6561, 3^{x - 3} = ?$
$3^{x - 3} = \frac{3^{x}}{3^{3}} = \frac{3^{x}}{27} = \frac{6561}{27} = 243$ .

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