If 30% of the visitors to an ice cream shop have chocolate ice-cream, then what is the probability that 2 out of 3 people who entered the store on Saturday at 5 pm will have chocolate ice-cream?

0.16

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0.15

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0.19

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0.28

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Solution

The correct option is C 0.19
Probability of a success= 0.3

Probability of a failure= 0.7

Required Probability = 0.3 $\times$ 0.3 $\times$ 0.7 $\times$ $^{3}$ C $_{1}$ = 0.189

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Similar questions

Q. If 30% of the visitors to an ice cream shop have chocolate ice-cream, then what is the probability that 2 out of 3 people who entered the store on Saturday at 5 pm will have chocolate ice-cream?

Q. The table below shows the number of people who had the different ice creams at an ice cream parlour on a Saturday and a Sunday. Select the correct bar graph from the options given below:

Ice Creams.	Mango	Vanilla	Almond	Chocolate
No. of people who had different ice creams on Saturday	20	30	25	35
No. of people who had different ice creams on Sunday	25	35	40	50

48 ice-creams are placed on a table. Some are chocolate flavoured and others are vanilla flavoured. If I take an ice-cream at random from the table, the probability that it is chocolate flavoured is 2/3. Find the number of vanilla flavoured ice-creams on the table.

48 ice-creams are placed on a table. Some are chocolate flavored and others are vanilla flavored. If a person takes an ice-cream at random from the table, the probability that it is chocolate flavored is $\frac{2}{3}$ . Find the number of vanilla flavored ice-creams on the table.

Q. Jax and Jane have some Ice-creams of different flavors. There are Chocolate Ice- creams.

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If 30% of the visitors to an ice cream shop have chocolate ice-cream, then what is the probability that 2 out of 3 people who entered the store on Saturday at 5 pm will have chocolate ice-cream?

The correct option is C 0.19Probability of a success= 0.3 Probability of a failure= 0.7 Required Probability = 0.3 × 0.3 × 0.7 × 3C1 = 0.189

The correct option is C 0.19
Probability of a success= 0.3

Probability of a failure= 0.7

Required Probability = 0.3 $\times$ 0.3 $\times$ 0.7 $\times$ $^{3}$ C $_{1}$ = 0.189