If $30$ % students failed in English, $45$ % failed in Math and $25$ % failed in both then the student who pass in both subjects is?

38

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55

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70

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50

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Solution

The correct option is D $50$ %
Given,
Number of students fail in Math $P (m) = 45$

Number of students fail in English $P (e) = 30$

Number of students fail in both the subject $P (m \cap e) = 25$

Number of studnts who pass both subject

$= 100 - [P (m) + P (e) - P (m \cap e)] = 100 - (30 + 45 - 25) = 100 - 50 = 50$ %

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If 30% students failed in English, 45% failed in Math and25% failed in both then the student who pass in both subjects is?

The correct option is D 50%Given,Number of students fail in Math P(m)=45Number of students fail in English P(e)=30Number of students fail in both the subject P(m∩e)=25Number of studnts who pass both subject=100−[P(m)+P(e)−P(m∩e)]=100−(30+45−25)=100−50=50%

If $30$ % students failed in English, $45$ % failed in Math and $25$ % failed in both then the student who pass in both subjects is?