If $300 m L$ of a gas at $27^{o} C$ is cooled to $7^{o} C$ at constant pressure, its final volume will be:

135 m L

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540 m L

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350 m L

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280 m L

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Solution

The correct option is B $280 m L$
According to Charle's law:
$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$
now,
$\frac{300}{300 K} = \frac{V_{2}}{280 K} = \frac{300 \times 280}{300}$
=280 ml
then $V_{2}$ = 280 ml

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