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Silicates

If 31g of P4 ...

Question

If 31g of $P_{4}$ is reacted with excess oxygen, the percentage yield is 60%, then the amount of product formed is?

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Solution

Step 1:
The chemical equation for the given reaction is:
$P_{4} + 5 O_{2} ⟶ P_{4} O_{10}$
$I f t h e y e i l d i s 100 %$
$(4 \times 31 g m o f P_{4}) g a v e = (4 \times 31 + 16 \times 10 g m) o f P_{4} O_{10}$
$T h e r e f o r e 31 g m o f P_{4} w i l l g i v e = \frac{31 \times 284}{124} g m o f P_{4} O_{10}$
$= 71 g m o f P_{4} O_{10}$
Step 2:
$H o w e v e r t h e y e i l d i s 60 %$
$H e n c e t h e a m o u n t o f p r o d u c t i s = 0.6 \times 71$
$A m o u n t o f p r o d u c t = 42.6 g m o f p r o d u c t$

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