If 31z5 is a multiple of 9, where z is a digit, what is the value of z? [2 MARKS]

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Solution

Concept: 1 Mark
Application: 1 Mark

The sum of digits of a number must be divisible by 9 for it to be divisible by 9.

3 + 1 + z + 5 = z + 9

Since z is a digit, z = 0, 9.

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