If $31 z 5$ is a multiple of $9$ , where $z$ is a digit, what is the value of $z$ ?

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Solution

The correct options are
C 9
D 0
Given that $31 z 5$ is a multiple of $9$ .
According to the divisibility rule of $9$ , the sum of all the digits should be a multiple of $9$ .
Therefore,
$3 + 1 + z + 5 = 9 O R 18$
$\Rightarrow z = 9 - 9 = 0$
$\Rightarrow z = 18 - 9 = 9$

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Question 2
If 31z5 is a multiple of 9, where z is a digit, what is the value of z?
You will find that there are two answers for the last problem. Why is this so?

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If 31z5 is a multiple of 9, where z is a digit, what is the value of z?

The correct options are C 9 D 0Given that 31z5 is a multiple of 9. According to the divisibility rule of 9, the sum of all the digits should be a multiple of 9. Therefore, 3+1+z+5=9 OR 18⇒z=9−9=0⇒z=18−9=9

If $31 z 5$ is a multiple of $9$ , where $z$ is a digit, what is the value of $z$ ?

The correct options are
C 9
D 0
Given that $31 z 5$ is a multiple of $9$ .
According to the divisibility rule of $9$ , the sum of all the digits should be a multiple of $9$ .
Therefore,
$3 + 1 + z + 5 = 9 O R 18$
$\Rightarrow z = 9 - 9 = 0$
$\Rightarrow z = 18 - 9 = 9$