If 323 - 41 - 14323- 137 - 72 - 27731- 48 - 87 - 7884 then 34 - 75 - -

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Byju's Answer

Standard XII

Mathematics

Combination of Atleast One Thing from n Things When All Are Not Different

If 323 × 41...

Question

If $323 \times 41 = 14323, 137 \times 72 = 27731, 48 \times 87 = 7884$ then $34 \times 75 = ?$

5473

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5743

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7534

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5734

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Solution

The correct option is B $5743$
Since, it's clear from the remaining series,
the pattern is seconds 2 digits are reversed and wrote first, then followed by the reversed first 2 digits.
$34 \times 75$

From,
$75$ to $57$
and
$34$ to $43$
So,
the answer is,
$5743$

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Similar questions

Q. If

323 \times 41 = 14323; 137 \times 72 = 27731

and

48 \times 87 = 7884

, then

34 \times 75 =

Q. If 32

\times

41=15; 51

\times

34= 46; 41

\times

52 = 37 then 87

\times

53 = ?

Q. If

32 \times 41 = 15; 51 \times 34 = 46; 41 \times 52 = 37

, then

87 \times 53 = ?

Q. What will be the result if -87 is subtracted from the sum of 34 and -75?

Find the median of the data
46, 41, 77, 58, 35, 64, 87, 92, 33, 55, 90.
In the above data, if 41 and 55 are replaced by 61 and 75 respectively, what will be the new median?

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If 323×41=14323,137×72=27731,48×87=7884 then 34×75=?

The correct option is B 5743Since, it's clear from the remaining series,the pattern is seconds 2 digits are reversed and wrote first, then followed by the reversed first 2 digits.34×75From,75 to 57and34 to 43So,the answer is,5743

If $323 \times 41 = 14323, 137 \times 72 = 27731, 48 \times 87 = 7884$ then $34 \times 75 = ?$

The correct option is B $5743$
Since, it's clear from the remaining series,
the pattern is seconds 2 digits are reversed and wrote first, then followed by the reversed first 2 digits.
$34 \times 75$

From,
$75$ to $57$
and
$34$ to $43$
So,
the answer is,
$5743$