Question

If 340 g of a mixture of $N_2$ and $H_2$ in the correct ratio gave 20% yield of $N{H}_3$, the mass of $N{H}_3$ produced would be:

• A. 16 g
• B. 17g
• C. 20 g
• D. 68 g

Answer 1

The correct option is D 68 g

The mass of mixture is 340 g.
The yield of ammonia is 20%.
The mass of ammonia produced $=\frac{20}{100}\times 340=68g$.