wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If 340 g of mixture of N2 and H2 in the correct ratio gave a 20% yield of NH3. The produced mass of NH3 would be:

A
16 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
17 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
20 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
68 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 68 g
According to the problem:
Given, the mixture is 340gm,
Yield %= 20

N2+3H22NH3

Therefore,
At NTP, 34gm of reaction mixture is equal to the 34gm of NH3

Hence, 340gm of reaction mixture is,
=3434×340=340gmofNH3

Percentage yield =obtainedproductmassexpctedproductmass×100

20=obtainedproductmass340×100

Hence the obtained product mass is 68 gram of NH3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Structural Isomerism
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon