If $35^{a} b = 3^{4} 5^{6} 7^{3}$ where a and b are both positive integers, then how many different values can b take?

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Solution

The correct option is C
3

$3^{4} 5^{6} 7^{3} = 3^{4} 35^{3} 5^{3}$

The question states that the given expression will be written as $35^{a} b$ where a and b are both positive integers, i.e. a can take values 1,2 or 3. For each of these values, b will have three different values. Hence answer is option (c).

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If 35ab=345673 where a and b are both positive integers, then how many different values can b take?

The correct option is C 3 345673=3435353 The question states that the given expression will be written as 35ab where a and b are both positive integers, i.e. a can take values 1,2 or 3. For each of these values, b will have three different values. Hence answer is option (c).

If $35^{a} b = 3^{4} 5^{6} 7^{3}$ where a and b are both positive integers, then how many different values can b take?