If $(3 a^{2} + 1) - (4 + 2 a^{2}) = 0$ , find the value of $a$ .

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Solution

We have,

$(3 a^{2} + 1) - (4 + 2 a^{2}) = 0$

$3 a^{2} + 1 - 4 - 2 a^{2} = 0$

$a^{2} - 3 = 0$
$a = \pm 3$
Hence, this is the answer.

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