If 3a+2b+4c=26 and6b+4a+2c=48 then a+b+c= ?

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In acute angled triangle $A B C, r + r_{1} = r_{2} + r_{3}$ and $∠ B > \frac{π}{3}$ then

3 a - 2 b + 4 c

3 b - 2 c

a - b - c

∣ ∣ ∣ ∣ \begin{matrix} a & a + b & a + b + c 2 a & 3 a + 2 b & 4 a + 3 b + 2 c 3 a & 6 a + 3 b & 10 a + 6 b + 3 a \end{matrix} ∣ ∣ ∣ ∣ = a^{3}

[\to a \to b \to c] = - 2

[\to a + 2 \to b, \to b - 2 \to c, \to c + 3 \to a] =

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