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Byju's Answer
Standard XII
Mathematics
Manipulation of a linear equation
If 3A = 4B = ...
Question
If 3A = 4B = 6C, find A : B : C is 4 : 3 : 2
A
True
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B
False
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Solution
The correct option is
A
True
3
A
=
4
B
=
6
C
3
A
=
4
B
=
>
A
B
=
4
3
This means,
A
:
B
=
4
:
3
4
B
=
6
C
=
>
B
C
=
6
4
=
3
2
=
>
B
:
C
=
3
:
2
The value of B in
4
:
3
is equal to the value of B in
3
:
2
Therefore,
A
:
B
:
C
=
4
:
3
:
2
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0
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