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Question

If 3A=∣∣ ∣∣−1−2−221−2x−2y∣∣ ∣∣T such that AAT=I, then which of the following are correct ?

A
x+2y=4
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B
xy=1
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C
x2+y2=3
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D
x2+y2=5
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Solution

The correct options are
B x+2y=4
C xy=1
D x2+y2=5
3A.3AT=∣ ∣12x21222y∣ ∣∣ ∣122212x2y∣ ∣
=∣ ∣ ∣1+4+x22+22x24+xy2+22x4+1+4422y24+xy422y4+4+y2∣ ∣ ∣=∣ ∣900090009∣ ∣
(AAT=I)
5+x2=9,42x=0,422y=0,xy=2
i.e.x=2,y=1

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