If 3m−5m=−1 and 2m=n−3 find the value of (3m+5n) and (m+2n).
-11, -4
3m−5n=−1...(i)
2m=n−3...(ii)
Multiplying (i) by 2 and (ii) by 3 and subtracting (ii) from (i) -
6m−10n−(6m−3n)=−2+9
⇒ -7n=7 ⇒ n=-1
Substituting value of n (ii), we get
2m−(−1)=−3⇒2m+1=−3
⇒2m=−4⇒m=−2
\((3m+5n) =3(-2)+5(-1) \\
=-6-5=-11 \)
and \((m+2n)=-2+2(-1) \\
=-2-2=-4\)