If $(3 p + q, p - q) = (p - q, 3 p + q)$ , then:

p = q = 0

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p = q

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p = 2 q

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p + q = 0

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Solution

The correct option is D $p + q = 0$
As the ordered pairs are equal,
$3 p + q = p - q$
$=> 2 p = - 2 q$
$=> 2 p + 2 q = 0$
$=> p + q = 0$

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