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(x±a)(x±b) = x²±(a+b)x+ab.

If 3x-1=9 and...

Question

If 3^x^-1 = 9 and 4^y⁺² = 64, what is the value of $\frac{x}{y}$ ?

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Solution

We have to find the value of for

So,

By equating the exponent we get

Let’s take

By equating the exponent we get

By substituting in we get

Hence the value of is

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(x±a)(x±b) = x²±(a+b)x+ab.

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