If $3 x = 13$ and $2 y = 7$ , what is the value of $3 (2 x) - 2 (3 y)$ ?

5

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Solution

The correct option is A $5$
Given,
$3 x = 13$
$2 y = 7$
so, $x = \frac{13}{3}; y = \frac{7}{2}$
now , $3 (2 x) - 2 (3 y) = 3 \times (2 \times \frac{13}{3}) - 2 \times (3 \times \frac{7}{2}) = 5$

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Similar questions

Solve the following equations by trial and error
method:

$(1) x - 10 = 5$

$(2) \frac{a}{7} + 8 = 6$

$(3) x^{2} + 6 = 9$

$(4) 19 = x + 13$

$(5) \frac{x}{4} = 9$

$(6) 2 x + 4 = 3 x - 4$

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

Q. What is the value of

(\frac{1}{\sqrt{9} - \sqrt{8}} - \frac{1}{\sqrt{8} - \sqrt{7}} + \frac{1}{\sqrt{7} - \sqrt{6}} - \frac{1}{\sqrt{6} - \sqrt{5}} + \frac{1}{\sqrt{5} - \sqrt{4}})

Solve the following equations:

\frac{7}{3^{x}} - \frac{6}{2^{y}} = 15

;

\frac{8}{3^{x}} = \frac{9}{2^{y}}

Q. Solve for x & y

\frac{7}{3^{^{x}}} - \frac{6}{2^{y}} = 15

\frac{8}{3^{x}} = \frac{9}{2^{y}}

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If 3x=13 and 2y=7, what is the value of 3(2x)−2(3y)?

The correct option is A 5Given,3x=132y=7so,x=133;y=72now , 3(2x)−2(3y)=3×(2×133)−2×(3×72)=5

If $3 x = 13$ and $2 y = 7$ , what is the value of $3 (2 x) - 2 (3 y)$ ?

The correct option is A $5$
Given,
$3 x = 13$
$2 y = 7$
so, $x = \frac{13}{3}; y = \frac{7}{2}$
now , $3 (2 x) - 2 (3 y) = 3 \times (2 \times \frac{13}{3}) - 2 \times (3 \times \frac{7}{2}) = 5$