The correct option is A xϵ (10,∞ ) Given that, 3x+17 lt; 13 ⇒ 3x 17 gt;13 [multiplying by 1 on both sides] 3x gt;13+17 ...

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Properties of Inequalities

If -3 x+17<-1...

Question

If -3x+17<-13,then

$x ϵ (10, \infty)$

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$x ϵ [10, \infty)$

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$x ϵ (- \infty, 10]$

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$x ϵ [- 10, 10)$

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Solution

The correct option is A
$x ϵ (10, \infty)$

Given that,-3x+17<-13

$\Rightarrow 3 x - 17 > 13 [multiplying by -1 on both sides] 3 x > 13 + 17 [multiplying by 17 on both sides] \Rightarrow 3 x > 30 ∴ x > 10$

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Similar questions

X = 28 + (1 \times 2 \times 3 \times 4 \times . . . . . \times 16 \times 28)

Y = 17 + (1 \times 2 \times 3 \times . . . . . . \times 17)

X - Y

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3, x, 17

x

{(\frac{17}{18})}^{x - 1} = {(\frac{18}{17})}^{x - 3}

L e t f (x) = \frac{g (x)}{x} w h e n x \neq 0 a n d f (0) = 0 . I f g (0) = g^{1} (0) a n d g^{11} (0) = 17 t h e n f^{1} (0)

f (x - 1) = 3 x^{2} + 5 x + 6

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