If 3x + 2y = 12 and xy = 6, find the value of 9x2+ 4y2

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Solution

Given,
3x+2y=12 , xy=6

(3x+2y)^2 =12^2

=9x^2+4y^2+12xy=144

ie, 9x^2+4y^2+(12×6)=144
=9x^2+4y^2+72=144

9x^2+4y^2=144-72
=72.

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