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Question

If 3x2y=13 and xy=5 , find the value of 27x38y3

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Solution

3x2y=13
(3x2y)2=132
9x2+4y212xy=169
9x2+4y2+6xy=169+18xy=169+90=359
27x38y3=(3x)3(2y)3
=(3x2y)(9x2+4y2+6xy)
=(13)(359)=4667

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