If (3x−4)(5x+7)=15x2−ax−28, then a = _____.
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Given (3x−4)(5x+7)=15x2−ax−28 ⇒15x2−20x+21x−28=15x2−ax−28 ⇒15x2+x−28=15x2−ax−28 On comparing the coefficient of x on both the sides, we get −a=1 So, a=−1
If (3x−4)(5x+7)=15x2−ax−28, then find the value of a.