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Question

If 3x=cosecθ and 3x=cotθ, find the value of 3x2-1x2. [CBSE 2010]

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Solution

3x2-1x2=93x2-1x2=139x2-9x2=133x2-3x2
=13cosecθ2-cotθ2=13cosec2θ-cot2θ=131=13

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