3x = sec@ ---------- 1 3/x = tan@-----------2
x = sec@/3 1/x = tan@/3
x2 =sec2@/9 1/x2 = tan2@/9
x2 - 1/x2 =sec2@/9 - tan2@/9
= (sec2@ - tan2@) / 9
9( x2 - 1/x2 ) = 1 since sec2@ - tan2@ = 1 note : theta = @
If 3x=secθ,3x=tanθ, then find the value of x2−1x2