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Question

If 3x2¯ is a multiple of 11, where x is a digit, what is the value of x?

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Solution

Sum of the digits at odd places = 3+2= 5Sum of the digit at even place = x Sum of the digit at even place-Sum of the digits at odd places=(x-5) (x-5) must be multiple by 11. Possible values of (x-5) are 0, 11, 22, 33...But x is a digit; therefore x must be 0, 1 ,2, 3...9. x-5=0 x=5

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