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Question

If y=x4āˆ’10 and if x changes from 2 to 1.99, what is the change in y.

A
5.68
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B
0.32
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C
5.968
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D
0.032
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Solution

The correct option is B 0.32
We have,

y=x410
dydx=4x3
Given: Δx=2.001.99=0.01
Now, Δy=4x3×Δx
[Δy=dydx×Δx]
Δy=4×23×0.01[x=2]
Δy=32×0.01=0.32

Therefore, the approximate change in y is 0.32
Hence, option a is correct.

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