Question

If $4^{2x}=\frac{1}{32}$, then the value of x is

• A. $\frac{5}{4}$
• B. $-\frac{5}{4}$
• C. $\frac{3}{4}$
• D. $-\frac{5}{2}$

Answer 1

Answer: (B)

$-\frac{5}{4}$

$4^{2x}=\frac{1}{32}\Rightarrow (2^2{)}^{2x}=\frac{1}{2^5}$
$\Rightarrow 2^{4x}=2^{-5}$
$\Rightarrow 4x=-5$
$x=\frac{-5}{4}$