If 4- 3-x2- 12- then the value of xx-0a 16b 4c 9d 3

It is given that, 43=x212 #8658;4 #215;43 #215;4=x212 #8658;1612=x212 #8658;16=x2 #8658;42=x2 #160; #160; #160; #160; #160; #160; #16 ...

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Byju's Answer

Standard XII

Mathematics

Inequalities of Integrals

If 4: 3=x2: 1...

Question

If 4 : 3 = x² : 12, then the value of x (x > 0).

(a) 16
(b) 4
(c) 9
(d) 3

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Solution

It is given that,

$\frac{4}{3} = \frac{x^{2}}{12} \Rightarrow \frac{4 \times 4}{3 \times 4} = \frac{x^{2}}{12} \Rightarrow \frac{16}{12} = \frac{x^{2}}{12} \Rightarrow 16 = x^{2} \Rightarrow 4^{2} = x^{2} (∵ x > 0) \Rightarrow 4 = x$

Hence, the correct option is (b).

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If 4 : 3 = x2 : 12, then the value of x (x > 0). (a) 16 (b) 4 (c) 9 (d) 3

It is given that, 43=x212⇒4×43×4=x212⇒1612=x212⇒16=x2⇒42=x2 ∵ x>0⇒4=x Hence, the correct option is (b).

If 4 : 3 = x² : 12, then the value of x (x > 0).

(a) 16
(b) 4
(c) 9
(d) 3

It is given that,

$\frac{4}{3} = \frac{x^{2}}{12} \Rightarrow \frac{4 \times 4}{3 \times 4} = \frac{x^{2}}{12} \Rightarrow \frac{16}{12} = \frac{x^{2}}{12} \Rightarrow 16 = x^{2} \Rightarrow 4^{2} = x^{2} (∵ x > 0) \Rightarrow 4 = x$

Hence, the correct option is (b).