If 4/5,a,2 are three consecutive terms of AP , find the value of ' a '
Open in App
Solution
Since 4/5, a and 2 are consecutive terms, their common difference should be equal. a2 - a1 = a3 - a2 a - 4/5 = 2 - a a + a = 2 + 4/5 2a = 10/5 + 4/5 2a = 14/5 a = 14/5 x 1/2 a = 14/10 a = 7/5