If $4 a + 5 b + 9 c = 36$ and $7 a + 9 b + 17 c = 66$ , then $a + b + c =$

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Solution

$ 4a+5b+9c=36 $; ----(1)
$7a+9b+17c=66$;----(2)
⟹ (multiply 1st equation by 2)
$8a+10b+18c=72$;
$7a+9b+17c=66$;
Then subtract equations:
$a+b+c=(8a+10b+18c)−(7a+9b+17c)=6$

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Similar questions

If 4a+5b+9c=36 and 7a+9b+17c=66 then find the value of a+b+c

- 5 a^{2} + 3 a - 5 b^{2}

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(4 a + 9 b) (4 c - 9 d) = (4 a - 9 b) (4 c + 9 d)

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(7 a - 9 b)

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