If 4cos2θ+15cosθ−4=0, find the value of (log2cosθ)−5:
If a=14(2x−1),b=−15(4x+1), a-b=2, Find the value of x.
If a=14(2x−1),b=−15(4x+1), a-b=2, find the value of x.
If a=√5+1√5−1and b=√5−1√5+1,the value of(a2+ab+b2a2−ab+b2)is :