The correct option is B 80
Here, x1+x2+x3+x4=10
6≥x1,x2,x3,x4≥1
Since the minimum value of every dice will be 1
∴X1+1+X2+1+X3+1+X4+1=10⇒X1+X2+X3+X4=6
Where 5≥X1,X2,X3,X4≥0
Total ways =6+4−1C4−1=9C3=84
Now subtracting those cases when any Xi=6
There will be 4 cases
∴ Required number of ways
=84−4=80