Question

If -4 is a zero of the polynomial $x^2-x-(2+2k)$ then the value of k is

• A. 3
• B. 6
• C. -9
• D. 9

Answer 1

The correct option is D 9

One of the zero of the polynomial is -4

When x=-4,p(x)=0

Put the value of the x in given polynomial

$\Rightarrow (-4{)}^2-(-4)-(2+2k)=0$

$\Rightarrow 16+4-2-2k=0$

$\Rightarrow 18-2k=0$

$\Rightarrow -2k=-18$

$\Rightarrow k=\frac{-18}{-2}=9$