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If -4 ≤ 4 x +...

Question

If $- 4 \leq 4 x + 4 \leq 8$ , then maximum value of $x$ is

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Solution

Given
$- 4 \leq 4 x + 4 \leq 8 \Rightarrow - 4 - 4 \leq 4 x + 4 - 4 \leq 8 - 4 \Rightarrow - 8 \leq 4 x \leq 4 \Rightarrow - 2 \leq x \leq 1$

Hence maximum value of $x$ is $1$

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