Question

If $4\left(x\right)=x+\left[x\right];x>0$ then the value of $x$ which satisfies, lies in the interval

• A. $\left[0,1\right]$
• B. $\left(2,3\right)$
• C. $\left(1,2\right)$
• D. $\left(5,6\right)$

Answer 1

The correct option is A $\left[0,1\right]$

$4\left(x\right)=x+\left[x\right];x>03x=\left[x\right]$

Since both are increasing functions.

we can say that equality holds when

$x=0$

so, $x=0$ is only solution lying in $[0,1]$