If $4$ mol of $B r_{2}$ undergo a loss and gain of a total of $6$ mol electrons to form two new oxidation state of $B r_{2}$ . How many moles of $B r_{2}$ acts as reductant?

One

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Two

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Three

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Four

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Solution

The correct option is A One
When 4 moles of bromine undergo a loss and gain of six mole electrons to form two new oxidation state of bromine, 1 mole of bromine acts as reductant, its oxidation number changes from 0 to +5. Thus, it is oxidized. 5 moles of bromine act as oxidant. Its oxidation number changes from 0 to -1.

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