If 4 sin−1x+cos−1x=π then x is equal to
-1/2
0
1/2
1
4 sin−1x+cos−1x=π ⇒4 sin−1x+(π2−sin−1x)=π ⇒3 sin−1x=π−π2=π2 ⇒sin−1x=π6 ⇒x=sinπ6=12