If 4 tan-3- evaluate 4 sin-cos-1-4 sin-cos-1-

Ans. nbsp;4 tan⁡θ=3 tan⁡θ = 3/4 By applying pythagoras theorem, we will get sinθ = nbsp;3/5 cosθ = nbsp;4/5 4sinθ cosθ+1/ nbsp;4sin⁡θ+cos⁡θ 1 4(3/5) ...

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Standard XII

Physics

Introduction

If 4 tan⁡θ=3,...

Question

If 4 tan⁡θ=3, evaluate (4 sin⁡θ-cos⁡θ+1)/(4 sin⁡θ+cos⁡θ-1).

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Solution

Ans. 4 tan⁡θ=3
tan⁡θ = $\frac{3}{4}$
By applying pythagoras theorem, we will get
sinθ = $\frac{3}{5}$
cosθ = $\frac{4}{5}$
$\frac{4 s i n θ - c o s θ + 1}{4 s i n θ + c o s θ - 1}$
$\frac{4 (\frac{3}{5}) - (\frac{4}{5}) + 1}{4 (\frac{3}{5}) + (\frac{4}{5}) - 1}$
$\frac{(\frac{12}{5}) - (\frac{4}{5}) + 1}{(\frac{12}{5}) + (\frac{4}{5}) - 1}$
= $\frac{13}{11}$

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If 4 tan⁡θ=3, evaluate (4 sin⁡θ-cos⁡θ+1)/(4 sin⁡θ+cos⁡θ-1).

Ans. 4 tan⁡θ=3 tan⁡θ = 34 By applying pythagoras theorem, we will get sinθ = 35 cosθ = 45 4sinθ−cosθ+14sinθ+cosθ−1 4(35)−(45)+14(35)+(45)−1 (125)−(45)+1(125)+(45)−1 = 1311