If $4 \times 10^{20} e V$ of energy is required to move a charge of $0.25$ coulomb between two points, the p.d between them is:

256 V

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512 V

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123 V

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215 V

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Solution

The correct option is A $256 V$
$4 \times 10^{20} e V = 4 \times 10^{20} \times 1.6 \times 10^{- 19} = 64 J$
So $E = 64 = V \times Q = 0.25 V$
$V = 256 V$

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