Question

If $4\times {10}^{-3}joules$of work is done in moving a particle carrying a charge of $16\times {10}^{-6}coulombs$ from infinity to point P, what will be the potential at point P?

Answer 1

Step 1

Given data

1. Work done in moving a charged particle is $W$= $4\times {10}^{-3}J.$
2. The charge on the particle is $Q=16\times {10}^{-6}C.$

Step 2

Finding the potential at point P

The potential at point P is given by,

$V=\frac{W}{Q}$

where $V$is the potential at point P.

Substituting the known values,

$$\begin{gathered} V=\frac{4\times {10}^{-3}J}{16\times {10}^{-6}C} \\ V=250V \end{gathered}$$

Thus, the potential at point P is $250V$.