If 4 a- -5 b- -9 c-0- then a-b- - -b-c- - c-a- is equal to

The correct option is B 0 Let, 4a⃗+5b⃗+9c⃗=0 ......(1).Now, (a⃗×b⃗)×[(b⃗×c⃗)×(c⃗×a⃗)] =(a⃗×b⃗)×[{(b⃗×c⃗).a⃗}c⃗ {(b⃗×c⃗).c⃗}a⃗] . =(a⃗×b ...

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Work Done as Dot Product

If 4 a⃗ +5 ...

Question

If $4 \to a + 5 \to b + 9 \to c = 0$ , then $(\to a \times \to b) \times [(\to b \times \to c) \times (\to c \times \to a)]$ is equal to

a vector perpendicular to the plane of

\to a, \to b

and

\to c

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a scalar quantity

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Vector quantity

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Similar questions

\to a, \to b, \to c

\to a \times (\to b + \to c) + \to b \times (\to c + \to a) + \to c \times (\to a + \to b)

\to A = \to b \times \to c, \to B = \to c \times \to a, \to C = \to a \times \to b

\to A \times (\to B \times \to C)

\to B \times (\to C \times \to A)

\to C \times (\to A \times \to B)

\to a, \to b

\to c

| \to a - \to b |^{2} + | \to b - \to c |^{2} + | \to c - \to a |^{2} = 9

| 2 \to a + 5 \to b + 5 \to c |

\to a, \to b

\to c

| \to a | = \sqrt{3}, | \to b | = 5, \to b . \to c = 10

\to b

\to c

\frac{π}{3} .

\to a

\to b \times \to c

| \to a \times (\to b \times \to c) |

\to a + \to b + \to c = 0

\to a \times \to b = \to b \times \to c = \to c \times \to a

\to a, \to b, \to c

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