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Question

If 4x22+x+5+||b1|3|=|siny|, where x,y,bR has a real solution, then the maximum possible value of b is

A
8
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B
2
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C
0
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D
4
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Solution

The correct option is D 4
4x22+x+5+||b1|3|=|siny|22x42x+4+1+||b1|3|=|siny|(2x2)2+1+||b1|3|=|siny|
We know that |siny|[0,1]
Also,
(2x2)2+1+||b1|3|1
So equality is possible only when
(2x2)2=0 and||b1|3|=0siny=±1y=(2n+1)π2 and x=1 andb=2,4

Hence, the maximum value of b is 4.

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