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Expansion of (x^2 - y^2)

If 4^x - 4^x-...

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If 4^x - 4^{x-1} = 24, then (2x)x equals to what?

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4^{x} - 4^{x - 1} = 24

(2 x)^{x}

4^{x} - 4^{x - 1} = 24,

then the value of

(2 x)^{x}

4^{x} - 4^{x - 1} = 24,

what is the value of

{(2 x)}^{x} ?

4^{x} - 4^{x - 1} = 24

then find the value of

(2 x)^{x} .

4 x - 4 x^{- 1} = 24,

then (2x)^x equals

(a)

5 \sqrt{5}

\sqrt{5}

25 \sqrt{5}

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