If 4- x1- x2- x3- 28 are in AP- then x3- -a 19b 23c 22d cannot be determined

(c) 22 Here, nbsp;a nbsp;= 4, nbsp;l nbsp;= 28 and n = 5 Then, T5 nbsp;= 28 rArr; nbsp;a nbsp;+ nbsp;(n 1)d = 28 rArr; 4 + (5 1)d= ...

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Byju's Answer

Standard X

Mathematics

Solving a Quadratic Equation by Factorization Method

If 4, x1, x2,...

Question

If 4, x₁, x₂, x₃, 28 are in AP, then x₃ = ?
(a) 19
(b) 23
(c) 22
(d) cannot be determined

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Solution

(c) 22

Here, a = 4, l = 28 and n = 5
Then, T₅ = 28
⇒ a + (n - 1)d = 28
⇒ 4 + (5 - 1)d= 28
⇒ 4d = 24
⇒ d = 6
Hence, x₃ = 28 - 6 = 22

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If 4, x1, x2, x3, 28 are in AP, then x3 = ? (a) 19 (b) 23 (c) 22 (d) cannot be determined

(c) 22 Here, a = 4, l = 28 and n = 5 Then, ​T5 = 28 ⇒​ a + (n - 1)d = 28 ⇒​ 4 + (5 - 1)d= 28 ⇒ 4d = 24 ⇒ d = 6 Hence, x3 = 28 - 6 = 22

If 4, x₁, x₂, x₃, 28 are in AP, then x₃ = ?
(a) 19
(b) 23
(c) 22
(d) cannot be determined

(c) 22

Here, a = 4, l = 28 and n = 5
Then, T₅ = 28
⇒ a + (n - 1)d = 28
⇒ 4 + (5 - 1)d= 28
⇒ 4d = 24
⇒ d = 6
Hence, x₃ = 28 - 6 = 22