If 40 g of calcium has 'x' atoms, then the number of atoms in 40 g neon will be (Given- atomic mass of calcium= 40 u, atomic mass of neon= 20 u)

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Solution

Dear student,

As the atomic mass of calcium= 40u
Therefore the no. of atoms present in 40g of calcium= 6.023 x 10²³atoms

The atomic mass of neon is= 20u
given mass of neon is 40g
The no. of atoms present in 20g neon will be = 6.023 x 10²³ atoms
The no. of atoms present in 1g neon will be = 6.023 x 10²³ / 20 atoms

Hence the no. of atoms present in 40g of neon = (6.023 x 10²³ x 40) / 20 atoms
= 12.046 x 10²³ atoms
Regards

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