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Question

If 43Cr − 6 = 43C3r + 1 , then the value of r is
(a) 12
(b) 8
(c) 6
(d) 10
(e) 14

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Solution

(a) 12

r - 6 + 3r + 1 = 43 [∵nCx=nCy n=x+y or x=y]
4r - 5 = 43 4r = 48 r = 12

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