Question

If $\frac{4}{5},a,2$ are three consecutive terms of an AP, then a = ?
(a) 5
(b) $\frac{5}{4}$
(c) $\frac{9}{5}$
(d) $\frac{7}{5}$

Answer 1

(d) $\frac{7}{5}$

If $\frac{4}{5}$, a and 2 are three consecutive terms of an AP, then we have:
a - $\frac{4}{5}$ = 2 - a
⇒ 2a = 2 + $\frac{4}{5}$
⇒ 2a = $\frac{14}{5}$
⇒ a = $\frac{7}{5}$