If $\frac{4}{5}$ of a cistern is filled in 1 minute, how much time will be required to fill the empty cistern?

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Solution

Time taken to fill $\frac{4}{5}$ of the cistern = 1 min

Time taken to fill 1 cistern = $\frac{1}{\frac{4}{5}} = \frac{5}{4}$ = 1.25 min = 1 min 15 sec
Hence, it will take 1 min 15 sec to fill the empty cistern.

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Similar questions

Q. A tap A can fill a cistern in 4 hours and the tap B can empty the full cistern in 6 hours. If both the taps are opened together in the empty cistern, in how much time will the cistern be filled up?

Q. Mark (✓) against the correct answer
If

\frac{4}{5}

of a cistern is filled in 1 minute, how much more time will be required to fill the rest of it?

(a) 20 seconds
(b) 15 seconds
(c) 12 seconds
(d) 10 seconds

A pipe can fill a cistern in 9 hours. Due to leak in its bottom , the cistern fills up in 10 hours. If the cistern is full , in how much time will it be emptied by leak ?

Two pipes A and B can separately fill a cistern in 60 minutes and 75 minutes respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 minutes. In how much time the third pipe alone can empty the cistern?

Q. Two pipes

A

and

B

can separately fill a cistern in

60 m i n u t e s

and

75 m i n u t e s

respectively. There is a third pipe at the bottom of the cistern to empty it , If all the three pipes are simultancously opened, then the cistern is full in

50 m i n u t e s

, In how much time, the third pipe alone can empty the cistern ?

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If 45 of a cistern is filled in 1 minute, how much time will be required to fill the empty cistern?

Time taken to fill 45 of the cistern = 1 min Time taken to fill 1 cistern = 145=54= 1.25 min = 1 min 15 sec Hence, it will take 1 min 15 sec to fill the empty cistern.

If $\frac{4}{5}$ of a cistern is filled in 1 minute, how much time will be required to fill the empty cistern?

Time taken to fill $\frac{4}{5}$ of the cistern = 1 min

Time taken to fill 1 cistern = $\frac{1}{\frac{4}{5}} = \frac{5}{4}$ = 1.25 min = 1 min 15 sec
Hence, it will take 1 min 15 sec to fill the empty cistern.